NUR 617 Module 5 Assignment 2: One-Way ANOVA in SPSS Example

Reviewed by Ingrid Vasterling, MSN, RN Arizona State University Updated October 2026

This NUR 617 Module 5 sample is Assignment 2, the one-way ANOVA work for Foundational Concepts in Science and Statistics, which ASU's Regulatory and Clinical Research Management doctoral students take early in the program. Set beside Chapter 7 of Polit's text, ASU NUR 617 expects an ANOVA run in SPSS on the supplied data, with the output tables placed in the answer file, an interpretation and replies to concept questions. The composite research coordinator analyzes an illustrative dataset of 60 participants who gave consent by paper form, electronic consent or teach-back discussion, then completed a comprehension measure. Her F test is not significant. She reports it correctly with eta squared, reads the Tukey comparisons without overclaiming, explains what a nonsignificant ANOVA does and does not show, and estimates the sample a confirmatory study would need.

CourseNUR 617 Foundational Concepts in Science and Statistics
ModuleModule 5
Paper typeSPSS data analysis assignment with output and interpretation
LengthAbout 870 words, 6 pages
FormatAPA 7 student paper
SchoolArizona State University
ProgramDoctorate of Professional Practice in Regulatory and Clinical Research Management
UpdatedOctober 2026

Free sample paper for NUR 617 Module 5

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Paper, Screen or Teach-Back? A One-Way ANOVA of Consent Comprehension Scores and How to Report a Nonsignificant Result

Student Name

Edson College of Nursing and Health Innovation, Arizona State University

NUR 617: Foundational Concepts in Science and Statistics

Instructor Name

Month Day, Year

What this page is doingThe title names the three groups being compared and signals early that the result was not significant, which is the main lesson of the analysis.
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Paper, Screen or Teach-Back? A One-Way ANOVA of Consent Comprehension Scores and How to Report a Nonsignificant Result

Data and Research Question

Students analyze a dataset supplied in Canvas. For this sample, an invented dataset was generated to demonstrate the same procedure, and its values belong to no actual study. The scenario is a methods substudy at a clinical research site. Sixty adults enrolling in a low-risk observational study were randomly assigned to one of three consent formats: a standard paper consent form read with staff (n = 20), an electronic consent with short embedded videos (n = 20) or a paper form followed by a structured teach-back discussion (n = 20). Immediately afterward, each participant completed the objective knowledge section of the Quality of Informed Consent questionnaire (QuIC), scored 0 to 100, where higher totals mean fuller understanding (Joffe et al., 2001).

The research question was whether mean comprehension differs across the three consent formats. With one categorical independent variable of three levels and one interval-level outcome, the appropriate test is a one-way analysis of variance. Under the null hypothesis the three formats share one population mean; the alternative says that at least one mean differs. Alpha was set at .05.

What this page is doingThe section names the independent variable, its levels, the outcome and the reason ANOVA fits before any numbers appear, which is the logic Chapter 7 asks students to show.
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Assumption Checks

One-way ANOVA assumes independent observations, a roughly normal outcome within each group and equal variances across groups (Polit, 2010). Independence holds because each participant was assigned to only one format. Shapiro-Wilk tests within groups were not significant (paper, p = .205; electronic, p = .710; teach-back, p = .572), and histograms showed no marked skew. Levene's test of homogeneity of variance was not significant, F(2, 57) = 0.77, p = .468, so the standard F test and the Tukey HSD post hoc procedure are appropriate. Group sizes are equal, which also makes ANOVA more robust to small violations.

What this page is doingAll three assumptions are tested and reported with the statistic and p value, and the writer notes how equal group sizes add protection, a point that shows understanding rather than a checklist.
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SPSS Output

Descriptives: QuIC Part ANMeanStd. DeviationStd. Error
Paper consent2072.858.541.91
Electronic consent2076.4510.972.45
Teach-back2076.908.101.81
Total6075.409.311.20
ANOVA: QuIC Part ASum of SquaresdfMean SquareFSig.
Between groups197.10298.551.14.326
Within groups4919.305786.30
Total5116.4059
Tukey HSD Multiple ComparisonsMean DifferenceSig.95% CI
Paper minus electronic-3.60.443-10.67 to 3.47
Paper minus teach-back-4.05.359-11.12 to 3.02
Electronic minus teach-back-0.45.987-7.52 to 6.62

Interpretation

Mean comprehension was lowest with paper consent (M = 72.85, SD = 8.54), higher with electronic consent (M = 76.45, SD = 10.97) and highest with teach-back (M = 76.90, SD = 8.10). The one-way ANOVA did not show a statistically significant difference among the three formats, F(2, 57) = 1.14, p = .326. The effect size, eta squared = 197.10 / 5116.40 = .039, means that consent format accounted for about 4% of the variation in comprehension scores, a small effect by conventional benchmarks (Lakens, 2013).

Because the omnibus F test was not significant, the post hoc comparisons should not be used to claim differences between particular pairs. They are reported here because the assignment requests them, and they agree with the F test: no pair differed significantly, and every confidence interval includes zero. The intervals are also wide. The paper versus teach-back interval runs from about 11 points in favor of teach-back to 3 points in favor of paper, so the data are compatible both with no difference and with a gain large enough to matter to an institutional review board.

What this page is doingThe writer reports the nonsignificant F test in full APA form, calculates eta squared from the table and explains why the Tukey results are shown but not used for claims, which is the judgment the conceptual part of the assignment tests.
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Conceptual Questions

Why use ANOVA instead of three t-tests? Running three separate t-tests at alpha = .05 raises the chance of at least one false positive across the set to roughly 14%. ANOVA tests all three means at once at a single alpha, and post hoc procedures such as Tukey's adjust for the number of comparisons.

What does F represent? F is the ratio of the variance between group means to the variance within groups. Here the between-groups mean square (98.55) was only slightly larger than the within-groups mean square (86.30), so the group means differed by little more than chance would produce.

Does a nonsignificant result show that consent format makes no difference? No. A nonsignificant result means the data did not provide enough evidence to reject the null hypothesis. With 20 per group, the study had low power to detect a small effect. Treating eta squared of .039 as the expected effect (f of about 0.20), a power analysis in G*Power for three groups at alpha = .05 and power = .80 calls for roughly 240 participants, about 80 per group (Faul et al., 2007). The direction of the means is consistent with reviews that found extended discussion with participants among the more reliable ways to improve understanding (Flory & Emanuel, 2004), which is a reason to test the question properly rather than abandon it.

What this page is doingThe final answer separates "not significant" from "no effect," supports the point with a worked power estimate and links the pattern to published reviews without claiming the illustrative data confirm them.
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Conclusion

In this illustrative substudy, comprehension did not differ significantly across paper, electronic and teach-back consent, and the effect of format was small. The result is best read as inconclusive rather than negative: the confidence intervals are wide, the study was underpowered for a small effect and the observed ordering matches prior evidence. A confirmatory comparison would need roughly four times the sample.

References

Faul, F., Erdfelder, E., Lang, A.-G., & Buchner, A. (2007). G*Power 3: A flexible statistical power analysis program for the social, behavioral, and biomedical sciences. Behavior Research Methods, 39(2), 175-191. https://doi.org/10.3758/BF03193146

Flory, J., & Emanuel, E. (2004). Interventions to improve research participants' understanding in informed consent for research: A systematic review. JAMA, 292(13), 1593-1601. https://doi.org/10.1001/jama.292.13.1593

Joffe, S., Cook, E. F., Cleary, P. D., Clark, J. W., & Weeks, J. C. (2001). Quality of informed consent: A new measure of understanding among research subjects. Journal of the National Cancer Institute, 93(2), 139-147. https://doi.org/10.1093/jnci/93.2.139

Lakens, D. (2013). Calculating and reporting effect sizes to facilitate cumulative science: A practical primer for t-tests and ANOVAs. Frontiers in Psychology, 4, Article 863. https://doi.org/10.3389/fpsyg.2013.00863

Polit, D. F. (2010). Statistics and data analysis for nursing research (2nd ed.). Pearson.

Reading the NUR 617 Module 5 assignment instructions

Week 5 brings Assignment 2, worth 20 points and tied to Chapter 7 on one-way analysis of variance. The routine matches the other two analysis assignments: open the instruction file from Canvas, analyze the supplied data in SPSS, write your answers in the file with the relevant tables pasted beside them and submit it. Four verbs from the syllabus define every assignment: analyze, produce output, interpret and explain the concepts. For ANOVA that usually means a question that compares three or more groups on one outcome, assumption checks including homogeneity of variance, the ANOVA table, a post hoc procedure and questions on why ANOVA is used and what F means. The same week also holds Discussion Board 3, so plan both deadlines together.

How the NUR 617 Module 5 example is put together

Like a finished answer document, this sample begins with a disclosure that the dataset is illustrative and then defines the groups, the measure and the research question. It names the test and gives the reason it fits. A short assumptions section reports each check with its statistic, including Levene's F with both degrees of freedom. Output follows in three tables laid out as SPSS presents them: descriptives, the ANOVA summary and the Tukey comparisons. The interpretation gives the APA results sentence, calculates eta squared from the sums of squares and explains why post hoc comparisons are not used for claims after a nonsignificant F. Conceptual answers cover inflated error with multiple t-tests, the meaning of F and what a null result does not prove, with a worked power estimate.

NUR 617 Module 5 rubric: what earns full marks

Look in Canvas for the Assignment 2 rubric, since the syllabus gives only the 20-point value. Analysis assignments are generally scored on choosing and running the correct procedure, presenting the right output, reporting results accurately and explaining concepts in your own words. In an ANOVA, frequent deductions come from omitting the effect size, reporting F without both degrees of freedom, interpreting post hoc tests as if the omnibus test were significant and treating a null finding as evidence that the groups match. Clear statements of what the result means for the research question, in plain language, distinguish the strongest submissions. Feedback arrives within 72 hours of the due date under the syllabus, early enough to use before Assignment 3, and late work loses 10% a week.

NUR 617 Module 5 help: mistakes that cost marks

Students often stop at "p > .05, so there is no difference," which is the claim faculty most often correct. Say the result was not significant and explain what that leaves open. Another frequent miss is skipping the effect size; calculate eta squared by dividing the between-groups sum of squares by the total. Report F as F(2, 57) = 1.14, with both degrees of freedom, and do not round p to zero. If your F test is significant, use the Tukey table to say which pairs differ and by how much; if it is not, say so and keep the post hoc results in their place. Paste only the tables the questions use. Should you want a second look, share your ANOVA tables and the Canvas questions with the desk and a model interpretation can follow your figures.

Write yours, or have the desk draft it

This paper is an original model document written by our desk, not a submitted student paper and not an official Arizona State University document. Read it for the moves, then write your own to the instructions in your classroom. If you want one built to your exact prompt and rubric, the first custom sample is free and arrives in 24 to 48 hours.

More NUR 617 and Doctorate of Professional Practice in Regulatory and Clinical Research Management sample papers

NUR 617 Module 5 questions, answered

Where can I find a free NUR 617 Module 5 sample paper?

A full NUR 617 Module 5 sample is above: an Assignment 2 answer document with a one-way ANOVA on illustrative consent data, assumption checks, SPSS tables, eta squared, Tukey results and conceptual answers.

How do I report a one-way ANOVA in APA style?

Give each group's mean and standard deviation, then F with its two df values, the exact p and eta squared, as in F(2, 57) = 1.14, p = .326, eta squared = .039.

Should I run post hoc tests if the ANOVA is not significant?

Post hoc tests are meant to locate differences after a significant F; if F is not significant, report them only if asked and do not use them to claim pair differences.

How do I calculate eta squared from SPSS output?

Divide the between-groups sum of squares by the total sum of squares in the ANOVA table; the result is the proportion of variance explained by group membership.

What chapter does NUR 617 Assignment 2 cover?

It is tied to the seventh chapter of the Polit text, on one-way analysis of variance, and falls due at the close of Week 5.